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||
0 ignored issues
–
show
Unused Code
introduced
by
![]() The variable
Symbol seems to be never declared. If this is a global, consider adding a /** global: Symbol */ comment.
This checks looks for references to variables that have not been declared. This is most likey a typographical error or a variable has been renamed. To learn more about declaring variables in Javascript, see the MDN. ![]() There is no return statement if
!n.isReady is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() There is no return statement if
"undefined" != typeof b.getElementById && p is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() Usage of the sequence operator is discouraged, since it may lead to obfuscated code.
The sequence or comma operator allows the inclusion of multiple expressions where only is permitted. The result of the sequence is the value of the last expression. This operator is most often used in Used in another places it can make code hard to read, especially when people do not realize it even exists as a seperate operator. This check looks for usage of the sequence operator in locations where it is not necessary and could be replaced by a series of expressions or statements. var a,b,c;
a = 1, b = 1, c= 3;
could just as well be written as: var a,b,c;
a = 1;
b = 1;
c = 3;
To learn more about the sequence operator, please refer to the MDN. ![]() Curly braces around statements make for more readable code and help prevent bugs when you add further statements.
Consider adding curly braces around all statements when they are executed conditionally. This is optional if there is only one statement, but leaving them out can lead to unexpected behaviour if another statement is added later. Consider: if (a > 0)
b = 42;
If you or someone else later decides to put another statement in, only the first statement will be executed. if (a > 0)
console.log("a > 0");
b = 42;
In this case the statement if (a > 0) {
console.log("a > 0");
b = 42;
}
ensures that the proper code will be executed conditionally no matter how many statements are added or removed. ![]() There is no return statement if
q is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() |
|||
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0 ignored issues
–
show
There is no return statement if
a && 3 !== a.nodeType &&...= a.nodeType && a.style is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() There is no return statement if
b is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() There is no return statement if
k && j.k && e || j.k.dat...| "string" != typeof b is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() Usage of the sequence operator is discouraged, since it may lead to obfuscated code.
The sequence or comma operator allows the inclusion of multiple expressions where only is permitted. The result of the sequence is the value of the last expression. This operator is most often used in Used in another places it can make code hard to read, especially when people do not realize it even exists as a seperate operator. This check looks for usage of the sequence operator in locations where it is not necessary and could be replaced by a series of expressions or statements. var a,b,c;
a = 1, b = 1, c= 3;
could just as well be written as: var a,b,c;
a = 1;
b = 1;
c = 3;
To learn more about the sequence operator, please refer to the MDN. ![]() There is no return statement if
this !== ra() && this.focus is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() There is no return statement if
i.0 = a, a.delegateTarge...ch.call(this, a) !== !1 is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() There is no return statement if
M(a) is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() Curly braces around statements make for more readable code and help prevent bugs when you add further statements.
Consider adding curly braces around all statements when they are executed conditionally. This is optional if there is only one statement, but leaving them out can lead to unexpected behaviour if another statement is added later. Consider: if (a > 0)
b = 42;
If you or someone else later decides to put another statement in, only the first statement will be executed. if (a > 0)
console.log("a > 0");
b = 42;
In this case the statement if (a > 0) {
console.log("a > 0");
b = 42;
}
ensures that the proper code will be executed conditionally no matter how many statements are added or removed. ![]() There is no return statement if
i = m = e = e || d, 3 !=...gger.apply(e, c) !== !1 is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() There is no return statement if
f = typeof c , "string" ...=== c = g.set(a, c, d)) is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() |
|||
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||
0 ignored issues
–
show
There is no return statement if
3 !== f && 8 !== f && 2 !== f is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() Usage of the sequence operator is discouraged, since it may lead to obfuscated code.
The sequence or comma operator allows the inclusion of multiple expressions where only is permitted. The result of the sequence is the value of the last expression. This operator is most often used in Used in another places it can make code hard to read, especially when people do not realize it even exists as a seperate operator. This check looks for usage of the sequence operator in locations where it is not necessary and could be replaced by a series of expressions or statements. var a,b,c;
a = 1, b = 1, c= 3;
could just as well be written as: var a,b,c;
a = 1;
b = 1;
c = 3;
To learn more about the sequence operator, please refer to the MDN. ![]() There is no return statement if
f is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() There is no return statement if
a.crossDomain is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() Curly braces around statements make for more readable code and help prevent bugs when you add further statements.
Consider adding curly braces around all statements when they are executed conditionally. This is optional if there is only one statement, but leaving them out can lead to unexpected behaviour if another statement is added later. Consider: if (a > 0)
b = 42;
If you or someone else later decides to put another statement in, only the first statement will be executed. if (a > 0)
console.log("a > 0");
b = 42;
In this case the statement if (a > 0) {
console.log("a > 0");
b = 42;
}
ensures that the proper code will be executed conditionally no matter how many statements are added or removed. ![]() There is no return statement if
e is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() There is no return statement if
!l.radioValue && "radio"... n.nodeName(a, "input") is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() There is no return statement if
this.0 is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() A for in loop automatically includes the property of any prototype object, consider checking the key using
hasOwnProperty .
When iterating over the keys of an object, this includes not only the keys of the object, but also keys contained in the prototype of that object. It is generally a best practice to check for these keys specifically: var someObject;
for (var key in someObject) {
if ( ! someObject.hasOwnProperty(key)) {
continue; // Skip keys from the prototype.
}
doSomethingWith(key);
}
![]() There is no return statement if
!b.crossDomain || l.cors is false . Are you sure this is correct? If so, consider adding return; explicitly.
This check looks for functions where a Consider this little piece of code function isBig(a) {
if (a > 5000) {
return "yes";
}
}
console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined
The function This behaviour may not be what you had intended. In any case, you can add a
![]() |
|||
5 | })}),n.each({Height:"height",Width:"width"},function(a,b){n.each({padding:"inner"+a,content:b,"":"outer"+a},function(c,d){n.fn[d]=function(d,e){var f=arguments.length&&(c||"boolean"!=typeof d),g=c||(d===!0||e===!0?"margin":"border");return Y(this,function(b,c,d){var e;return n.isWindow(b)?b.document.documentElement["client"+a]:9===b.nodeType?(e=b.documentElement,Math.max(b.body["scroll"+a],e["scroll"+a],b.body["offset"+a],e["offset"+a],e["client"+a])):void 0===d?n.css(b,c,g):n.style(b,c,d,g)},b,f?d:void 0,f,null)}})}),n.fn.extend({bind:function(a,b,c){return this.on(a,null,b,c)},unbind:function(a,b){return this.off(a,null,b)},delegate:function(a,b,c,d){return this.on(b,a,c,d)},undelegate:function(a,b,c){return 1===arguments.length?this.off(a,"**"):this.off(b,a||"**",c)}}),n.fn.size=function(){return this.length},n.fn.andSelf=n.fn.addBack,"function"==typeof define&&define.amd&&define("jquery",[],function(){return n});var nc=a.jQuery,oc=a.$;return n.noConflict=function(b){return a.$===n&&(a.$=oc),b&&a.jQuery===n&&(a.jQuery=nc),n},b||(a.jQuery=a.$=n),n}); |
||
0 ignored issues
–
show
The variable
define seems to be never declared. If this is a global, consider adding a /** global: define */ comment.
This checks looks for references to variables that have not been declared. This is most likey a typographical error or a variable has been renamed. To learn more about declaring variables in Javascript, see the MDN. ![]() Usage of the sequence operator is discouraged, since it may lead to obfuscated code.
The sequence or comma operator allows the inclusion of multiple expressions where only is permitted. The result of the sequence is the value of the last expression. This operator is most often used in Used in another places it can make code hard to read, especially when people do not realize it even exists as a seperate operator. This check looks for usage of the sequence operator in locations where it is not necessary and could be replaced by a series of expressions or statements. var a,b,c;
a = 1, b = 1, c= 3;
could just as well be written as: var a,b,c;
a = 1;
b = 1;
c = 3;
To learn more about the sequence operator, please refer to the MDN. ![]() |
|||
6 |